2006-11-08 11:52:41 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5a^2 + 3a - 2 = 0
can be factored as (5a - 2) (a + 1) = 0
Thus a = 2/5 and a = -1
2006-11-08 11:55:54 · answer #1 · answered by naglibog 2 · 1⤊ 0⤋
7
2006-11-08 19:53:55 · answer #2 · answered by Mark Antony 3 · 0⤊ 1⤋
(a + 1) (5a - 2) = 0
what are the factors of 5 and 2
since the last number is a negative - then 1 of
the signs is negative - and since the middle
number is poistive - the larger combo is positive
2006-11-08 19:57:58 · answer #3 · answered by tom4bucs 7 · 0⤊ 0⤋
5a^2+3a-2=0
first you factor, if you can
(5a-2)(1a+1)=0
Next, you divide the problem into two
(5a-2)=0 and (1a+1)=0
Now, solve each respective equation
5a-2=0
5a=2
a=2/5
and
1a+1=0
1a=-1
a=-1
Now, put your two answers into a set of numbers that fit the diameters of the problem:
a={2/5, -1}
2006-11-08 20:34:11 · answer #4 · answered by Christie 3 · 0⤊ 0⤋
a=2/5 or negative 1
2006-11-08 20:01:01 · answer #5 · answered by cmag62890 1 · 0⤊ 0⤋
-1 and .4 (2/5)
2006-11-08 19:56:32 · answer #6 · answered by Anonymous · 1⤊ 0⤋
no solution cause the two numbers cancel each other out (2)
2006-11-08 20:00:51 · answer #7 · answered by Anonymous · 0⤊ 0⤋