For the linear equation,
(y+4) = 1/3 (x+2)
For the above linear equation, what are the coordinates of the point on the line (as indicated by point - slope notation) as well as the slope of the line.
2006-11-08 11:39:17 · 6 answers · asked by The Ultimate Answerer 3 in Science & Mathematics ➔ Mathematics
The slope is 1/3 and the point is (-2, -4).
2006-11-08 11:42:19 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
We need to get the equation in point-slope form (y = mx + b):
y + 4 = 1/3x + 2/3
y = 1/3x + 2/3 - 4
y = 1/3x -3 1/3
So slope (m) = 1/3
the y-intercept is where x =0, so a point on the line is:
(0, -3 1/3)
Best of luck!
2006-11-08 19:43:47 · answer #2 · answered by disposable_hero_too 6 · 0⤊ 0⤋
(y+4) = 1/3 (x+2)
y+4 = 1/3 x + 2/3
y = 1/3 x - 10/3 <---- Slope notation
y intercept = [0, -10/3]
slope = 1/3
x intercept = , set y=0
0 = 1/3 x - 10/3
10/3 = 1/3 x
10 = 10
x intercept = [10,0]
2006-11-08 19:42:58 · answer #3 · answered by theicemanno77 2 · 0⤊ 0⤋
Point-slope notation is
y - y1 = m (x - x1)
where (x1,y1) is the point, and m is the slope.
Thus,
- the coordinates of the point is (-2, -4) and
- the slope is 1/3
Hope that helps =)
2006-11-08 19:42:08 · answer #4 · answered by Silver 2 · 1⤊ 0⤋
the obvious one is the y-intercept (0, -10/3).
(1, -3) , (-2, -4) , (10, 0)
2006-11-08 19:46:21 · answer #5 · answered by naglibog 2 · 0⤊ 0⤋
need y=mx+b
y= x/3+14/3
2006-11-08 19:42:42 · answer #6 · answered by bubsir 4 · 0⤊ 0⤋