Chalk consists mainly of calcium carbonate, a solid that tends to be insoluble in water, but abe to dissolve in aqueous acids. If a box of chalk contains twenty pieces of chalk, and each piece has a mass of 10.0g, how many moles of calcium carbonate are present in the entire box?
2006-11-08 10:42:24 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
First, find the total mass of chalk in the box:
(10 g)(20 pieces of chalk) = 200 g of chalk
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Calcium carbonate has a molecular formula of CaCO_3. Find the molecular mass to find the # of moles in the box of chalk.
Ca = 40.078
C = 12.0107
O = 15.994
Thus, molecular mass = 40.078 + 12.0107 + 3(15.994) ----->
100.07 g
Now perform the conversion to find the # of moles:
(200 g CaCO_3)(1 mol CaCO_3 / 100.07 g CaCO_3).
Thus, we have:
2 mol CaCO_3
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Hope this helps
2006-11-08 10:47:13 · answer #1 · answered by JSAM 5 · 0⤊ 0⤋
Take 1 box chalk, which is given. Multiply by 20pieces/1 box. The boxes cancel out, and you have 20 pieces. Next multiply by 10g chalk/1 piece. The pieces cancel, and you have 200g chalk. Chalk is calcium carbonate, CaCO3. CaCO3 has a mole weight of Ca=40 +C=12 +O3=48 = 100. Multiply the 200g CaCO3 by 1 mole CaCO3/100g CaCO3. The grams CaCO3 cancel to yield 2 moles CaCO3.
2006-11-08 11:01:34 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
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2016-05-16 01:53:19 · answer #3 · answered by Anonymous · 0⤊ 0⤋
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2016-12-10 05:28:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2 moles (CaO/CaCo3)= 56gCaO/100.CaCO3 = 1.12mol of CaO
2006-11-08 11:23:28 · answer #5 · answered by bige1236 4 · 0⤊ 1⤋