Help, I have a maths exam tomorrow and I don't know how to plot y=-1 on a graph.?

Question

Its crazy because i can do everything else but i always get confused about how to plot x=4 or y=3 on a graph. I always get confused.

Answer 1

I ususlly think that if an equation such as y = -1 doesn't have an x in it, then it won't hit the x-axis. The only way this could happen is if the line is horizontal, through -1 on the y-axis. Similarly, since x=4 has no y in it, it can't hit the y-axis and so must be vertical.

Answer 2

The graph axes (vertical line is Y axis, Horizontal is X axis) are numbered, with zero being the point where the two lines cross. If you want to plot a point, say, x=4, y=3,or (3,4), count three along the x axis, and then count (from this point) 4 upwards ie. up the y axis.

If you want to plot negative numbers, say x=1, y=-1, then count 1 along the x axis and (from that point) count 1 downwards ie. 1 down the y-axis.

The point you plot is specified by two co-ordinates, x and y (x,y). These numbers simply say "go x along the x axis, then y along the y axis"

Hope that helps :-)

Answer 3

Make yourself a chart with different values of x and the same value for y. Try (2, -1), (1, -1), (0, -1), (-1, -1), (-2, -2), and you should end up with a horizontal line one grid below the x-axis. Making a chart with x on one side and y on the other when you are unsure of how to graph it is usually the easiest way to see the plot. Good luck!

Answer 4

It's hard to explain without being able to draw but x is the horizontal axis and y is the verticle axis. x is positive on the right and negative to the left and y is positive on the top and negative on the bottom. If you want to plot y=(-1) the you go to the center of both the axis and go down one to negative one. If you want to plot x=4 then you go to the middle of the axis and to the right 4.

Answer 5

in regard to x^2 + bx + c = 0. a, b, or c characterize a variable (an integer, or any huge variety). enable us to declare the equation is x^2 - x -3 = 12. Now you could desire to set this equation to 0. you could desire to go the 12 to left hand element of the equation, and make the equation 0. so as that needless to say like this; x^2 - x - 3 - 12 = 0. x^2 -x - 15 = 0. Now as a thank you to locate the value of x, you could desire to element it. The factorization will appear like this; (x + 2)(x - 3) = 0... (x + 2) = 0, so x = - 2. do the comparable with the a number of element (x - 3) = 0, so x = 3. so x would desire to the two be - 2, or x would desire to be 3.

Answer 6

there is no x values so the line is going to have a slope of 0. In other words is just going to be a horizontal line at -1 in the y axis.

Answer 7

Okay, think about this way, what points should that give you?
It would give you (-1,-2) (0,-2), (1,-2), (2,-2) ,...(k,-2) such that k can be any number, right?
Then draw those numbers on a graph.
So, it just gives you a flat hortizonal line that gives you every point at y=-2, right?
So, thats how you get it!

Answer 8

the verticle line is y and the horizontal line is x. just look at the y line then go down to the bottom right square and find -1 on your graph if it is numbered.

Answer 9

just think of it as (0, -1)
go to the y axis and find -1 then there you go...if it's a line draw a straight horizontal line
think x=3 as (3,0) ...like that

Answer 10

ok listen when its x=4 so u place ur pencil on x=4 and then u trace a line parallel to the y'oy when its y=3 u trace one parallel to the x'ox
so if u have y=-1 then ur line should be parallel to the x'ox line
good luck in ur test
hope i helped u enough