a=1+3j
b=41-5j
2006-11-08 09:15:06 · 8 answers · asked by scoota 1 in Science & Mathematics ➔ Mathematics
5a = 5 + 15j
5b = 205 - 25j
5a - 5b = (5 + 15j) - (205 - 25j) = 5 - 205 + 15j + 25j = -200 + 40j
2006-11-08 09:20:55 · answer #1 · answered by wild_turkey_willie 5 · 0⤊ 0⤋
1
2006-11-08 09:18:01 · answer #2 · answered by maggieissohot 1 · 0⤊ 1⤋
5a - 5b = ?
5(1+3j) = 5 + 15j
5(41-5j)= 205 - 25j
5 + 15j - [205 - 25j]
5 + 15j - 205 + 25j
40j - 200 or 40(j-5)
OR DO IT THIS WAY
5(a-b)
5[(1+3j)-(41-5j)]
5[1+3j-41+5j]
5[8j-40]
5*8(j-5)
40(j-5)
2006-11-08 09:17:07 · answer #3 · answered by bourqueno77 4 · 0⤊ 0⤋
a=1;b=6
2006-11-08 09:20:48 · answer #4 · answered by j cool 1 · 0⤊ 0⤋
5a - 5b
5[1+3j] - 5[41 - 5j]
5+15j - 205 +25j
-205+5+15j+25j
-200 + 40j so that wud be ur answer
2006-11-08 09:21:48 · answer #5 · answered by Anonymous · 0⤊ 0⤋
5a + 5b = 5 + 15j + 205 - 25j = 210 + 40j
2006-11-08 09:20:07 · answer #6 · answered by luv_phy 3 · 0⤊ 0⤋
5a=5+15j
5b=205-25j
5+15j-(205-25j)
5-205+15j+25j
-200+40j
2006-11-08 09:20:05 · answer #7 · answered by ron 2 · 0⤊ 0⤋
-200-10j. i know thats not done all the way, but its as good as a 7th grade algebra student can get.
2006-11-08 09:19:58 · answer #8 · answered by someon 3 · 1⤊ 0⤋