BF3+LiSO3---->B2(SO3)3+LiF
CaCO3+H3PO4----->Ca3(PO4)2+H2CO3
Ag2S---->Ag+S8
2006-11-08 08:58:47 · 4 answers · asked by denise a 1 in Science & Mathematics ➔ Chemistry
2BF3 + 3Li2SO3 → B2(SO3)3 + 6LiF
3CaCO3 + 2H3PO4 → Ca3(PO4)2 + 3H2CO3
8Ag2S → 16Ag+S8
2006-11-08 09:11:39 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
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2006-11-08 16:59:46 · answer #2 · answered by jacket2230 4 · 0⤊ 0⤋
I think you need to figure out how to do these. I'll walk you through the first one, but I think you have an error in the formula for the lithium compound on the left. I think its formula should be Li2SO3. OK. So you've got 2 B on the right and only one on the left, so put a 2 in front of the BF3. That gives you six F on the left, so put a 6 in front of LiF on the right. That give you 6 Li on the right, so put a 3 in front of Li2SO3 on the left. Now, you've got 3 SO3 on the left and three on the right, and you're done.
Try the others in the same way. For the 2nd equation, I'd start with PO4 and then go from there, and for the third one, I'd start with the S.
Good luck
2006-11-08 17:15:36 · answer #3 · answered by hcbiochem 7 · 0⤊ 0⤋
2BF3 + 3Li2SO3 -----> B2(SO3)3 + 6LiF\
3CaCO3 + 2H3PO4 ----> Ca3(PO4)2 + 3H2O + 3CO2
4Ag2S ----> 4Ag + S8
2006-11-08 17:34:30 · answer #4 · answered by Lnc 1 · 0⤊ 0⤋