2006-11-08 08:57:46 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
gotta put the equation into y=mx+b first
y= 1/3x - 1
perpendicular would be y = -3x (+ or - any #)
2006-11-08 09:07:33 · answer #1 · answered by Meilleur_que_toi 4 · 0⤊ 0⤋
Perpendicular line have slopes whose product is -1.
It's useful to make a simple sketch to see this.
2006-11-08 17:03:02 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋
this is still a linear function, its form is just mx - y= B
the perpendicular slope is the negative inverse (-1/m)
so in this case, m= 1/3, so perpendicular slope is ...
-3
2006-11-08 17:01:57 · answer #3 · answered by Chris R 1 · 0⤊ 0⤋
1/3x-y=1
-y = 1 - 1/3x
-1(-y = 1 - 1/3x)
y = -1 -1/3x
slope=-1/3x
perpendicular slope=3x
y=mx+b
y=3x+b
2006-11-11 03:52:44 · answer #4 · answered by Raina 2 · 0⤊ 0⤋
-3
2006-11-08 17:14:01 · answer #5 · answered by J 6 · 0⤊ 0⤋