write this equation in point-slope form: containing (2,-4) and parallel to x-2y=5?

Answer 1

The slope intercept form is y=mx+b

So we rewrite the equation of the line as so:

x - 2y = 5 , subtract x from both sides
x - x -2y = 5 - x
-2y = 5 - x , now divide both sides by -2
-2y/-2 = (5 -x)/-2
y = -5/2 + x/2 , rearrange the left side
y = x/2 - 5/2

So the slope (m) is 1/2. Now we use the point given and the general equation. From the point we know that x=2 and y=-4. Sustitute these into the general equation.

y = mx +b
-4 = (1/2)2 + b , do the math
-4 = 2 + b ,subtract 2 from both sides
-4 - 2 = 2 - 2 +b
-6 = b

So the equation of the required line is:

y = x/2 - 6

Answer 2

first thing to know about parallel lines is that their slopes are equal. that means: -2y=5-x. then divide by -2 and you get
y=-5/2+x. slope is -5/2. then you need to put it into point-slope form, which is y-ysub1=m(x-xsub1) where ysub1 and xsub1 are the points and m is the slope.
y+4=-5/2(x-2). you can also simplify it some to get
y+4=-5/2x+5
y=-5/2x+1 but this last one is in slope-intercept form

Answer 3

y - (-4)=1/2 (x-2) Parallel slopes are equal.