find slope of a line that is perpindicular to this line: y=2x-3?

Question

please show me how to do this
algebra

Answer 1

For a line to be perpendicular all you need is the negative inverse slope.
y=2x-3 has a slope of 2 so the negative inverse would be (-1/2)

So y=(-1/2)x-3 would cross perpendicular at the y axis at -3

Answer 2

lines are perpendicular if their slopes are adverse reciprocals. y= 2x + 3 slope of the perpendicular line is -(a million/2) y = mx + b 2 = -(a million/2)(-4) + b 2 = 2 + b b = 0 So the equation is y = -(a million/2)x #21) x int is even as y=0 3x = 9 x =3 y int is even as x =0 2y -8 = 0 y = 4 2 factors on the line (3,0) and (0, 4) slope is (4-0) / (0 - 3) = -4/3 y int = 4 from above so y = -(4/3) x + 4

Answer 3

you divide -1 by the slope of your line to find the slope that is perpendicular to your line.

-1divided by 2 is -1/2, so -1/2 is the slope of the line perpendicular to y=2x-3

Answer 4

Y=mx + b

the slope of the perpendicular line is -1/m...


in this case m=2, so the slope of the perpendicular line is -1/2

Answer 5

-1/2

Answer 6

the slope of a perpendicular line is the negative reciprocal of the original line.

y=mx+b and y= -(1/m)x+b

So your perpendicular slope would be -1/2

y= (-1/2)x - 3

Answer 7

its -1/2.

Answer 8

-1/2


the 2 is the slope of the original line, so take the negative of the reciprical
-1/slope

Answer 9

ok.
heard of this rule?
let the gradient of a line be x, and the gradient of the perpendicular line be x'
x*x' = -1.

so the slopeof the perpendicula to this line is -1/2.

Hope this helps=)
apl

Answer 10

m1 - Slope of line one.
m2 - Slope of line two.

For perpendicular lines, m1 * m2 = -1.

Given: y = 2x - 3
→ m1 = 2

m1 * m2 = -1
2 * m2 = -1
m2 = -1/2

Answer: -1/2.