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1.) Cr(NO2)2+(NH4)2SO4---->CrSO4+NH4NO2
2.)KNO3+H2CO3----->K2CO3+HNO3
3.)KBr+Fe(OH)3----->KOH+FeBr3
4.)B2Br6+HNO3----->B(NO3)3+HBr

2006-11-08 08:19:01 · 3 answers · asked by denise a 1 in Science & Mathematics Chemistry

3 answers

1.) Cr(NO2)2+(NH4)2SO4
---->CrSO4+(2)NH4NO2
2.) (2)KNO3+H2CO3
----->K2CO3+(2)HNO3
3.) (3)KBr+Fe(OH)3
----->(3)KOH+FeBr3
4.) B2Br6+(6)HNO3
----->(2)B(NO3)3+(6)HBr

Hope this helps=)
Tip: Start by balancing those more isolated atoms first, especially when you are balancing more complex equations (they may have atoms that appear in more than 1 products).
Also, feel free to leave numbers in fractions while you balance ur equation. You can always multiply all the numbers later to make them all whole numbers. You will find this useful later when you have to balance long equations. Itd definitely more tedious to alter every number in ur mind and writing them all out at one go. Do it progressively=)

2006-11-08 08:42:58 · answer #1 · answered by luv_phy 3 · 0 0

what do you mean how can you balance them to me

2006-11-08 08:23:09 · answer #2 · answered by Anonymous · 0 1

OW!!!

2006-11-08 08:21:19 · answer #3 · answered by Anonymous · 0 2

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