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okay these are my math riddle we had to make and it has to be REALLY HARD. that the teacher cant find out. okay let me see if you can figure these TWO riddles out.

RIDDLE 1)
This number has 4 places to the right of the decimal point. It has 2 hundreds,3 ten thousanTHS, and 1 tenTH. It is in between 240 and 242 The thousandTHS place is one less than the ten thousandsTHS and less than the hundredTHS.What are six numbedrs that math the data?

RIDDLE 2)
This number has a 0 in the ones place. The fifth digit to the righr of the decimal sign is less than the first. The number in the thousandTHS lace is the smallest number.The number in the ten thousantHS place is half the value of the number on the hundreDS place. This decimal contain a 4,2,1,3 and 5.What is the number?

2006-11-08 08:00:05 · 5 answers · asked by holla! 2 in Science & Mathematics Mathematics

5 answers

I'm sorry, but there isn't enough information to solve either riddle. The one's digit in the first could be either o 0 or a 1, and there isn't enough information to determine the hundredths position.

In the second puzzle, you place a 0 in the one's place and go on to say that the number in the thousandths place is the smallest. This simply can't be.


Here'a a puzzle for you to try: Find the next number in the sequence: 1, 2, 2, 4, 8, 32

2006-11-08 08:10:37 · answer #1 · answered by Deirdre H 7 · 1 0

RIDDLE 1)

Here is the base number: 24X.1Y23
Using this, we can easily find six more numbers:
(1) 240.1323
(2) 240.1423
(3) 240.1523
(4) 240.1623
(5) 240.1723
(6) 240.1823

In all the ones above, I just changed the number in the hundredths place. We can do this because the only requirement that needs to be satisfied is that the number is greater than the number in the thousandths place (2).


RIDDLE 2)

Here is the answer: 0.54123


These problems were too easy. Your teacher will be able to do them both in less than a minute. You need to make them harder.


* To Dierdre: Both of the riddles can be easily solved, but you probably didn't read them carefully. Also, the answer to your problem is 256. Each number is the product of the two previous numbers: t(n) = t(n-2) * t(n-1)

2006-11-08 08:48:10 · answer #2 · answered by عبد الله (ドラゴン) 5 · 0 0

a million) the three adult males initiate out with $10 each and each ($10 x 3 = $30). 2) the three adult males pay $30 for a hotel room. Afterwards, a 5 greenback overcharge is returned to them ($25 + $5 = $30). 3) The bellboy divides up the $5 overcharge, returning $a million to each and all of the three adult males (for a complete of $3) and keeping $2 for himself ($25 + $3 + $2 = $30). the place did the lacking greenback flow? Nowhere. A greenback basically is going "lacking" because of the fact the fact "each and each guy paid $9 for the room" is faulty -- each and each of three adult males paid out a complete of $9, yet that $9 secure the two the room can charge and the bellboy's tip. All in all, each and each guy paid out a complete of $9 and had $a million left over, thoroughly accounting for the $30 they began with. The room value $25, so each and each guy paid one-0.33 of that value ($8.33). The bellboy saved a tip of $2, so each and each guy paid one-0.33 of that value ($0.sixty seven) besides. ordinary, each and each guy paid out $9 ($8.33 + $0.sixty seven) and had a greenback left over: (3 x $9) + (3 x $a million) = $27 + $3 = $30.

2016-10-21 12:04:52 · answer #3 · answered by ? 4 · 0 0

sounds like a homework assignment do your own homework!!!

2006-11-08 08:02:33 · answer #4 · answered by parrotsarenoisy 5 · 0 0

a) don't know, you need to use punctuation better.
b) 0.34125

2006-11-08 08:08:37 · answer #5 · answered by bourqueno77 4 · 0 0

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