Well, y=x/(x-1).
SO, y(x-1)=x, or yx-y=x.
So, yx-x=y, or x(y-1)=y, so x=y/(y-1).
So, that means y is any real number except 1.
So, the range is any real number except 1.
2006-11-08 07:40:00
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answer #1
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answered by yljacktt 5
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The range would include all real numbers--including y=1. The domain would be all real numbers excluding x=1.
2006-11-08 07:36:03
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answer #2
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answered by bruinfan 7
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' you can write y= x/(x-1)
then
(x-1) y =x
xy -y =x
x(y-1) =y
x = y/(y-1),
so the range of y is the domain of x, which in this case is all reals except y=1
2006-11-09 07:32:02
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answer #3
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answered by locuaz 7
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All real numbers except 1.
2006-11-08 07:34:02
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answer #4
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answered by MsMath 7
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