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Consider a point in the ocean about 10.9 km deep. The pressure at that point is huge, about 1.12 X10^8 N/m^2.
(a) What is the change in volume of 1.00 m^3 of water carried from the surface to this point in the ocean?
in m^3?

(b) The density of water at the surface is 1.03X10^3 kg/m^3. What is its density at this point?
in kg/m^3?

2006-11-08 07:19:09 · 3 answers · asked by activegirl 1 in Science & Mathematics Physics

3 answers

a) If the subject was a gas, you can use Boyle's Law to calculate the change in volume. The Boyle's Law states that the pressure of gas is inversely proportionate to its volume, and hence P1V1 = P2V2.
However, Boyles Law only covers the case of gas, and liquids are only VERY SLIGHTLY compressible. the volume of water doesnt really changes.

***Anyway, how do u even carry a litre of water in an ocean? u can use a bubble, and you cant use any use any hard cased material cos tt will prevent you from finding the change in volume!

b) ???
Unless you are so sure you can find the change in volume, the density remains the same. I don't know any formula similar to Boyles Law that can explain the relation between the pressure of water and its volume.

2006-11-08 07:39:21 · answer #1 · answered by luv_phy 3 · 0 0

Water is noncompressible. The volume is constant.

2006-11-08 07:21:08 · answer #2 · answered by terrypk 2 · 0 0

isn't water non compressible fluid?

2006-11-08 07:21:47 · answer #3 · answered by vijay_rao_nyc 2 · 0 0

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