An air bubble has a volume of 1.55 cm3 when it is released by a submarine 120 m below the surface of a lake.?

Question

What is the volume of the bubble when it reaches the surface? Assume that the temperature and the number of air molecules in the bubble remains constant during its ascent.

Answer 1

According to Boyles Law, P1V1 = P2V2
let p = rou, the density of pure water (assuming tt the lake is pure)[1000 kg/m^3]
Take g to be 10N/kg, and atmospheric pressure [P(atm)] to be 1.013x10^5 Pa

[P(pgh) + P(atm)] x 1.55 = P(atm) x New Volume
(1000x10x120 + 1.013x10^5) x 1.55 = 1.013x10^5 x new volume.
therefore,
new volume = 1210130 x 1.55 / 10130
= 185.16cm^3

Hope this helps =)

**The Boyles Law which i stated above states that the volume of gas in an enclosed area is inversely proportionate to its pressure. Initially under the water, the pressure on the bubble is taken to be atmospheric pressure + the weight of the column of water above it. As it rises, the pressure gradually decreases to only atmospheric pressure when it is at the surface. As such its volume increases proportionately, and tt's how i found out the ans.

Answer 2

I am a certified scuba diver, and if I recall every 33 feet the pressure increases by double (going down). That's all I have .

Answer 3

P = h?g, the place h denotes intensity of the ingredient, ? = density of fluid, and g = acceleration by using gravity use this formula to locate rigidity. and then use the certainty that quantity ? a million/rigidity.

Answer 4

is this supposed to be a joke or are u asking a question that is very difficult to answer