3x+5y=17..............equation no. (1)
3x+2y=14...............equation no. (2)
subtract (2) from (1)
3x+5y-3x-2y=17-14
3y=3
y=1
put this value of y in (1)
3x+5*1=17
3x+5=17
3x=17-5
3x=12
x=4
2006-11-08 05:15:22
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answer #1
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answered by Dupinder jeet kaur k 2
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x = 4 and y = 1
2006-11-08 05:07:27
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answer #2
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answered by princess 3
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y=1 thus x=4
2006-11-08 05:07:43
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answer #3
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answered by ♣ My Brainhurts ♣ 5
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x is 4 and y is 1
2006-11-08 05:07:04
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answer #4
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answered by Anonymous
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3x+5y=17 A
3x+2y=14 B
A-B= 3y=3 or y=1
Therefore putting value of y in A
we get 3x+5*1=17 or 3x=17-5=12 or x=4
therefore x=4 and y=1
2006-11-08 05:10:38
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answer #5
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answered by MY Regards to All 4
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Here's how I would do it, and I know it works because I plugged my answers back into the original problems...
Solve for X in the first equation...
x = 17 - 5y over 3 (the entire expression 17 - 5y is divided by 3)
Now use that for X in the second equation and solve for Y.
Use the answer you get for Y to solve for X.
You will get that y = 1 and x = 4.
2006-11-08 05:11:57
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answer #6
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answered by Anonymous
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3x +5y=17------->(1)
3x +2y=14-------->(2)
By elimination method
equation (1)-(2)
3x-3x=0;
5y-2y=3y
17-14=3
3y=3
y=1
subtitute y=1 into either of the equations.
i'll put equation (1)
3x+5(1)=17
grouping like terms
3x=17-5
3x=12
x=4
2006-11-08 05:41:53
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answer #7
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answered by Phy A 5
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I will start you off.
3x + 5y = 17, so 3x = 17 -5y.
Substitute 3x in second line with the above gives
17 -5y + 2y = 14.
17 -14 = 5y -2y
3 = 3y
2006-11-08 05:08:02
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answer #8
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answered by spiegy2000 6
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3x+5y=17
-
3x+2y=14
= 3y=3
therefore y = 1
so x must be 4
2006-11-08 05:15:02
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answer #9
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answered by matt151091 2
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