A garden area is 30 ft long and 20 ft wide. A path of uniform width is set around the edge. If the remaning garden area is 400 ft^2, what is the width of the path?
2006-11-08 04:54:06 · 2 answers · asked by Anonymous in Education & Reference ➔ Homework Help
the area of a rectangle is: a = b*h
So, the area with the path is 400 (given) = (30-2x)(20-2x)
400=600-100x+4x^2
0 = 200-100x+4x^2
0 = 50 - 25x +x^2
and then solve from there using quad eq.
addendum: using the quadratic equation, the answer is about 2.1922.
2 ft is not correct: the area you are trying to get is 400. if the path were 2 feet, then the area would be b * h = (30-4)(20-4) [the path goes all the way around so 2 ft from each side]. So 26*16=416.
2006-11-08 05:04:43 · answer #1 · answered by Grover 3 · 0⤊ 0⤋
2 foot
you got 600 square feet to start
and 400 square feet after the path
the path has a perimeter of 100 feet (30 + 20 + 30 + 20)
You are missing 200 sq ft after the path
200/100 = 2
2006-11-08 13:22:46 · answer #2 · answered by jinenglish68 5 · 1⤊ 1⤋