Please help to solve the equation for x?

Question

Factor the left hand side

x^2 + 4x + 4 = 7

Answer 1

x^2 + 4x + 4=7 (first put it in the form ax^2 + bx + c = 0, by subtracting 7 from both sides of the equation)

x^2 + 4x - 3 = 0 (this is called a quadratic equation)

Now substitute a =1, b = 4, c = -3 in the following formula

x equals -b plus or minus the square root of (b^2 - 4ac) all over 2a

Because you are solving for x^2 you expect to get 2 answers. The plus or minus in the middle of the formula gets you 2 answers as you solve the formula for both plus and minus the square root of (b^2 minus 4ac).

[If you're going to have to do this in an exam, it's probably worth learning the formula off by heart. It's boring to have to do so but you'll probably have more confidence in the exam if you see an quadratic equation and already know the formula.]

Good luck for the working out - you can do this bit!

Answer 2

(x+2)^2=7 is the left side factored

Answer 3

i do it with the method rosie recipe uses.
x^2 + 4x + 4 = 7
x^2 + 4x + 4 - 7 = 0
x^2 + 4x - 3 = 0
using the quadratic formula,
x = - [(b) +or - (route of b^2 - 4ac)]/2a
the answers are,
x = 0.345
x = (-4.35)

Answer 4

x^2+4x+4=7
x^2+2*2*x+2*2=7
(x+2)^2=7
(x+2)=+square root of 7 or -square root of 7
x=2+square root of 7 or 2-square root of 7