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Question

the pressure of the gas in the 1.00 L bulb is 676 mm Hg and that of the gas is the 0.500 L bulb is 431 mm Hg
What is the pressure (atm) of the system when both valves are opened, assuming the temperature remains constant ?
(neglect the volume of the capillary tube connecting the bulbs)

Answer 1

The easiest way to solve this problem is to figure out the amount of gas at a standard pressure for both of the bulbs. For example suppose that you pick 431mm Hg as the standard pressure then one bulb will have a volume of 1/2 L and the other would become 676/431 L or 1.568 L. Combine those two bulbs and you have 2.068L at 431mm Hg , now shrink the combined bulbs down to 1.5 L to get your answer and you would have 431 * 2.068 / 1.5 = 594 mm Hg