compare the address spaces of IPV6, IPV4 and IEEE 802 MAC addressing schemes.?

Answer 1

IPv4 is the addressing scheme in use today. It is made up of 32 bits, broken into 4 octets. It is commonly written in dotted decimal notation. You're probably familiar with this...ex: 192.168.1.1.

IPv6 is a more expansive version of IPv4 which will eventually be introduced in order to increase the number of available IP addresses. This address will be made up of 128 bits. Because the size of this would likely be unmanageable in dotted decimal, it will be represented in hexadecimal format.

MAC Addressing is somewhat different. This is the physical address of a piece of equipment. Unlike the IP addresses that identify a piece of equipment on a network somewhere, the MAC address is assigned to the physical equipment by the manufacturer or vendor, and in most cases, does not change. It is represented in a hexadecimal format.

Answer 2

MAC addresses in IPv4 are composed of twelve hexadecimal digits. each and each hexadecimal digit can handle one among sixteen values, so its handle area is composed of sixteen^12 values with the type 0000.0000.0000 to FFFF.FFFF.FFFF. (sixteen^12 = 281,474,976,710,656.) MAC addresses in IPv6 are composed of twenty-4 hexadecimal digits; subsequently, its handle area is composed of sixteen^24 values with the type 000:0000:0000:0000:0000:0000 - FFFF:FFFF:FFFF:FFFF:FFFF:FFFF. (sixteen^24 = seventy 9,228,162,514,264,337,593,543,950,336. it is seventy-9 octillion, 200 twenty-8 septillion, one hundred sixty-2 sextillion, fourteen quintillion, 200 sixty-4 quadrillion, 3 hundred thirty-seven trillion, ninety-3 billion, 40-3 million, 9 hundred fifty thousand, 3 hundred thirty-six.)