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the roots of eq: {(x)^n}-1=0 are called nth roots of unity. let these roots be denoted by 1,a,a1,a2........a(n-1)
1=e^(i2rpi) (r=0,1,2,3.......)

answer following-
1) value of (1-a1) (1-a2).......(1-a(n-1))is ?
2) value of sin pi/n,sin 2pi/n,sin3pi/n,........sin(n-1)pi/nis ?
3) value of a1*a2*a3*...........*a(n-1)=?
4) if a be the nth complex root of unity then (x+b)+(x2+b)a+(x3+b)a^2................+(xn+b)a^(n-1)

2006-11-08 01:26:30 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

2) value of sin pi/n,sin 2pi/n,sin3pi/n,........sin(n-1... ?

2006-11-08 01:35:13 · answer #1 · answered by AlOnEiNtHeRaIn 3 · 0 0

As far as I know the nth roots of unity are given by:

real = cos(2*m*pi/n), imag=sin(2*m*pi/n)

(with m=0,1,2,3...n-1)

2006-11-08 03:03:50 · answer #2 · answered by deflagrated 4 · 0 0

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