English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

please tell me the rules?

2006-11-08 01:17:51 · 4 answers · asked by stitch 1 in Science & Mathematics Mathematics

4 answers

log (ab)= log a + log b
log (a^p) = p log (a)
log (a/b) = log a - log b !

2006-11-08 01:43:08 · answer #1 · answered by Anonymous · 1 0

You have learned various rules for manipulating and simplifying expressions with exponents, such as the rule that says that x3 · x5 equals x8 because you can add the exponents. There are similar rules for logarithms.

Log Rules:

1) logb(mn) = logb(m) + logb(n)

2) logb(m/n) = logb(m) – logb(n)

3) logb(mn) = n · logb(m)

In less formal terms, the log rules might be expressed as:

1) Multiplication inside the log can be turned into addition outside the log, and vice versa.

2) Division inside the log can be turned into subtraction outside the log, and vice versa.

3) An exponent on everything inside a log can be moved out front as a multiplier, and vice versa.

(Just as when you're dealing with exponents, the above rules work only if the bases are the same. For instance, the expression "logd(m) + logb(n)" cannot be simplified, because the bases are not the same, just as x2 · y3 cannot be simplified.)

2006-11-08 01:24:34 · answer #2 · answered by Anonymous · 0 1

y = log a (x)
y is a subset of R
a > 0 and a <> 1
x >0

2006-11-08 01:21:08 · answer #3 · answered by James Chan 4 · 0 2

logA+logB=logAB (base is 10 everywhere)
logA-logB=logA/B
logA^B=BlogA

2006-11-08 02:44:08 · answer #4 · answered by arsenal rules 1 · 0 0

fedest.com, questions and answers