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3x - 3y = 9
-9x + 9y = -25

2006-11-08 01:00:53 · 4 answers · asked by Rocstarr 2 in Science & Mathematics Mathematics

4 answers

We'll use the "addition" (or "elimination") method, but if we were to use the substitution method, we'd get the same result.

If you multiply both sides of the first equation by 3, you'll get:

9x - 9y = 27

Adding the two equations together then produces:

9x - 9y - 9x + 9y = 27 - 25

When you combine like terms, you get

0 = 2

Now, obviously, that's not true, which means this is an "inconsistent system" -- a system without any solutions.

Hope that helps!

2006-11-08 01:06:49 · answer #1 · answered by Jay H 5 · 0 0

Solve for X in one equation and then substitute that in for the X in the other equation

3x = 9 -3y
x = 3 -y

Then,
-9(3-y) +9y = -25
-27 + 9y +9y = -25
18y = 2
y = 1/9

So, x = 2 8/9

2006-11-08 01:04:50 · answer #2 · answered by just browsin 6 · 0 1

In the first one, subtract 3x from both sides, and then divide the entire thing by -3:

y = x - 3

In the second, add 9x to both sides, and then divide the entire thing by 9:

y = x - 25/9

2006-11-08 01:04:16 · answer #3 · answered by Dave 6 · 0 1

You want to solve for one of the variables in one of the equations. Take the answer you get (ie y=3x) and put that in for the y in the other equation. Solve that equation you should find the value of x. Once you find the value of x, put that value in for x and solve for y.

2006-11-08 01:07:13 · answer #4 · answered by Michael D 1 · 0 0

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