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8 answers

The distance an object falls in time t is h = 0.5*g*t^2. In this case, g is 9.8 m/s^2 and t is 8 s, so h = 0.5(9.8)8^2 = 313.6 m.

Incidentally, the idea of throwing a thermometer off a building sounds like it was inspired by the legendary "barometer problem."

2006-11-08 00:38:39 · answer #1 · answered by DavidK93 7 · 0 0

S=(1/2)at^2
S=(1/2)(32)8^2
S=(16)(64)=1024ft
The thermometer was 1024 feet high but I couldn't
tell you exactly how high you were.

2006-11-08 00:48:56 · answer #2 · answered by albert 5 · 0 0

if you dropped it in vacuum, you are 320 meters above ground, which means that you could not see it hit the ground.
if you dropped it in the atmosphere, you are 275 meters maximum above ground (because of air friction), that also means you could not see it hit the ground
if you dropped in in water,I don't have the answer, not even a guess of how high you are, but it is possible that the height was much smaller, and you could see it hit the ground.

2006-11-08 00:43:40 · answer #3 · answered by Anonymous · 0 0

Mate, to me it sounds like your high as a kite. But physics was not one of my strong subjects. Get off the grass

2006-11-08 00:38:30 · answer #4 · answered by Rossco 4 · 0 0

8 seconds? I'd say you were pretty damn stoned. I wish I was that high...

2006-11-08 00:38:12 · answer #5 · answered by Xceed One 3 · 0 0

s=ut+1/2*a*t^2
u=0
t=8sec
a=9.81m/sec^2
s=1/2*9.81*64 m
=313.92 m

2006-11-08 00:44:20 · answer #6 · answered by openpsychy 6 · 0 0

whoa...a physics question??? oh man...sure is high logically...mayb 4 - 6 storeys high??

2006-11-08 00:48:53 · answer #7 · answered by Alicia 5 · 0 0

I depends - how much have you smoked?

2006-11-08 00:38:34 · answer #8 · answered by Anonymous · 0 0

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