well... the real and imaginary parts of this equation must be equal, so we can split it into two simultaneous equations:
x+y=4.4 and
x-y=-1.2
simply adding the two together gives us:
x+y+x-y=4.4-1.2
2x=3.2
x=1.6
and substituting x into one of our equations:
x+y=4.4
1.6+y=4.4
y=2.8
and, of course, its always worth checking that these figures work:
(x + y) +j(x - y)
1.6 + 2.8 + j(1.6-2.8)
=4.4+j(-1.2)
=4.4-j1.2
And we're done.
2006-11-08 00:22:49
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answer #1
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answered by robcraine 4
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I can think of no possible value to the equation! I can think of many values to not doing the equation, like going for a stroll with the dog, munching my way through a huge bar of chocolate. Even persuading you to give me 10 points for imagination.
2006-11-08 00:21:00
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answer #2
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answered by Anonymous
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I made it that x = 1.6
y = -0.933
j = 7.00
It took me ages and I think it is wrong, but you didn't ask for a correct answer. Here is the method, though:
First find x by dividing both sides by j to get rid of it.
Then when you have a value for x, put it back in to the equation as a number, and get rid of the y by dividing both sides by y, so that you get a value for j
Put the numerical values back in for j & x, giving you just one unknown (y) and work it to get a value for j.
That is what I did to get the values I gave at the top, but they seem wrong because when you put the values for x,y, & j back in, it does not equal.
Sorry! I really did try.
:-)
2006-11-08 00:36:22
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answer #3
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answered by superman in disguise 4
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That's a simple algebraic problem.
the real part of the right side of the equation must be equal to the real part of the left side
thus
x+y = 4.4
and
the imaginary part of the right side of the equation must be equal to the real part of the imaginary side
thus
x-y=-1.2
solving them simultneously.
x+y=4.4
x-y=-1.2
adding them will make it
2x = 3.2
x = 1.6
and subtracting them will make it
2y=5.6
y=2.8
therefore
x=1.6 and y=2.8
I'm expecting for the 10 points
thanks
2006-11-08 00:29:45
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answer #4
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answered by bhen 3
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I used to love quadratic equations ar school, but have not used them for 20 years and wouldn't know where to start!!!
2006-11-08 00:16:34
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answer #5
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answered by mrs2moo 1
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Surely you need to know the values of X or y?
Are you cheating by any chance? HA HA
2006-11-08 00:17:41
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answer #6
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answered by pinead101 3
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You have a pair of linear equations:
x+y = 4.4
x-y = -1.2
Add both equations together and simplify:
2x = 3.2
Hence, divide by 2 gives:
x = 1.6
Substitute in either equation above to give
y = 2.8
2006-11-08 00:27:15
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answer #7
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answered by Trevor P 2
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Another delightfully asked question. "Love" the demand for workings out as well.
Do it yourself.
2006-11-08 00:18:07
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answer #8
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answered by Anonymous
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separate real and imaginary
x+y=4.4............(1)
jx-jy= -j1.2
x-y= -1.2...........(2)
add (1) and (2)
2x=3.2>>>>>x=1.6
substitute into (1)
1.6+y=4.4>>>>>y=2.8
i hope that this helps
2006-11-08 01:26:15
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answer #9
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answered by Anonymous
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This can be done by equating coefficients.
2006-11-08 00:51:37
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answer #10
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answered by rajesh bhowmick 2
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