If an astronaut took a skydive...?

Question

20,000 feet above the moon's surface, an astronaut decided
to take a skydive . At what speed would he land?

Answer 1

The gravitational pull on the moons surface is quite low in comparison to the earth. That is while the earths gravitational pull is 9.8m/s 10newtons the moon is 0.1666667 meters per second if you compare a man who weights 100 kg on earth will weigh about 1.7007142857142857142857142857143 kgs using the 9.8m/s gravitational rule see that is very small. Also lets concider that there is no fluid resistance(resistance caused by the air molecues while moving downwards to the earths surface.)
then say that the astronaut dives from 20,000 feet from the sky(let see it on both senarios "earth,moon")also

20000feet= 6096meters
accelerations

earth=9.8m/s
moon=1.633366m/s

the speed will increase from 0m\s due to the increase in speed module =a=(v-u)/t
to find time you can use s=1/2at^2
acceleration on moon=1.633366m/s
v=at+u
v=final velocity
u=initial velocity=0;
t=sqrt(s/1/2a)
t=sqrt(6096/1/2*9.8)"On earth"=35.271seconds
t=sqrt(6096/1/2*1.633366)"On the moon"=86.396seconds
final acceleration on earth is
35.271*9.8+0=345.6558m\s on the earths surface
while on the moon!
gravitational acceleration on the moon is 1.633366 meters per second=about 0.167N
initial velocity =0;
final velocity =?
time taken=sqrt(6096/1/2*1.633366)= 86.396seconds

final speed=acceleration*time+initial speed

141.11696=m\s on the moons surface

now into feet
1meter =3.280 839 895 feet
141.116 96 meter = 462.982 152 231 feet\second

Answer 2

Use the following equations:
1. distance = 1/2 * accel * time * time
2. velocity = accel * time
----
Use the following facts:
accel on earth = 32 ft/sec/sec
accel on moon = 1/6 accel on earth = 5.33 ft/sec/sec
given distance = 20,000 feet
----
Solution:
Re-arranging equation 1:
time = square root ( 2 * distance/accel)
time = square root (40,000/5.33)
time = 86.23 sec [to fall 20,000 ft to moon surface]
----
Solving for velocity from equation 2:
velocity = accel * time
velocity = 5.33 * 86.23 = 459.6 ft/sec [speed at moon surface]

Answer 3

Where was he when he did this? If he was in an orbiting space craft, he would continue to orbit near his craft.

Answer 4

first he would be just floating then he would get into moon's atmoshphere thing i don't know how fast though

Answer 5

............... IT IS NOT THE LANDING ................. BUT HOW WILL HE COME BACK ................. ?? ........NOW START TO THINK ........... !!!!