2006-11-07 21:27:22 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
its my homework...lol....hope u can help...:) and thanks..
2006-11-07 21:29:28 · update #1
Since you are pretty, here's how:
1. Compute for the number of moles NaOH needed to prepare the solution.
mole NaOH: 1 L * 0.5 mol/L = 0.5 mol
2. Get the weight NaOH you need by multiplying the number of moles to the molecular mass of NaOH.
weight NaOH: 0.5 mol * 40g/mol = 20g
3. To prepare, weigh 20 grams of NaOH pellets. Dilute this with water to 1000 mL in a volumetric flask.
2006-11-07 22:09:00 · answer #1 · answered by titanium007 4 · 0⤊ 0⤋
Na=23, O=16, H=1. 23+16+1=40. 1 mole weighs 40g. What you require is 0.5 mole = 20g. Weigh carefully 20 grams of the NaOH . Put in a 1 liter glass ware. Add distilled water to the 1 liter mark.
2006-11-08 06:20:48 · answer #2 · answered by St Lusakan 3 · 0⤊ 0⤋