write the number of moles of H2O produced in a reaction of 50ml 1.0M HC2H3O2 and 50ml 1.0 M NaOH?

Answer 1

Find the moles of the acid CH3COOH and of the NaOH:

n = C*V = 1*0.05 = 0.05 mol CH3COOH

n = C*V = 1*0.05 = 0.05 mol NaOH

According to the balanced chem. equation:

CH3COOH + NaOH --> CH3COONa + H2O

1 mol of CH3COOH reacts with 1 mol of NaOH and gives 1 mol of H2O

So 0.05 mol CH3COOH reacts with 0.05 mol NaOH and gives 0.05 mol of H2O

That's the answer: 0.05 mol H2O

Answer 2

H2o Number

Answer 3

C2H4O2 + NaOH ---> NaC2H3O2 + H2O

since only one mole of H2O is produced for every mole of C2H4O2 and NaOH, number of moles H2O is 0.05mol.