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How much of an 8% saline solution should be added to 600 mL of a 3% solution to produce a 5% solution?

Please show ALL WORK and explain each step so that an eigth grader can understand it. Thanx sooo much!!!

2006-11-07 15:47:50 · 4 answers · asked by sonia 1 in Science & Mathematics Mathematics

4 answers

Suppose that we have r milliliters of the 8% solution. This means the amount of salt in it is .08r.
Suppose we have s milliliters of the 3% solution. This means that the amount of salt in it is .03s.
When we mix them together we have r + s milliliters total, and the amount of salt in it is .08r + .03s. If the resulting mixture is a 5% solution then this means that
(.08r + .03s)/(r + s) = .05.
So .08r + .03s = .05(r + s) = .05r + .05s.
Then .03r = .02s, or r/s = .02/.03 = 2/3.
But we know that s = 600 mL, so r = (2/3)s = (2/3)600 = 400 mL

Add 400 mL of the 8% solution to 600 mL of the 3% solution and get 1000 mL of 5% solution.

2006-11-07 17:18:26 · answer #1 · answered by wild_turkey_willie 5 · 0 0

subject # a million: Equation # a million: A = 3B Equation # 2: A - 6 = 2(B+6) A - 6 = 2B + 12 Subtract Eq #2 from Eq #a million to get Equation #3 Equation # 3: 6 = -B + 12 B = 12 - 6 (interchange B and six to get the fee of B) B = 6 (fee of B) Equation # a million: A = 3B A = 3(6) (replace B with 6 to get the fee of A) A = 18 (fee of A) subject # 2: Equation # a million: M = 2/3(H) Equation # 2: H = 20miles/6hours H = 10miles/3hours(cancellation) Equation # a million: M = 2/3(H) M = 2 10miles __ x ______ (substitution) then multiply 3 3hours M = 20miles/9hours answer: it is going to take 9hours for the mule to take the trip.

2016-12-28 15:45:47 · answer #2 · answered by ? 4 · 0 0

let v=volume added

.05=(600*.03+.08v)/(600+v)
.05(600+v)=18+.08v
30+.05v=18+.08v
12=.03v
v=12/.03=400ml

check
.03*600+.08*400=18+32=50g
400+600=1000 ml

50/1000=.05=5%

assuming density of 1g/ml

2006-11-07 15:53:20 · answer #3 · answered by yupchagee 7 · 0 0

Perhaps you should do your own homework...

2006-11-07 15:51:43 · answer #4 · answered by chubs 2 · 0 1

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