What is the Acceleration due to gravity on Jupiter? I need a site with a refrence from 1987 or older?

Answer 1

Jupiter has a "g" value of approx 26. The calculation can be made possible by simply knowing the Mass and Diameter of the planet, and by bearing in mind Issac's Newton's theory on gravitation.

Fgrav=(G*m1*m2)/(d*d)

where G is the universal gravitational constant = 6.67*10^ -11 Nm^2/kg^2
m1=mass of body 1
m2=mass of body 2
d=distance between body 1 and 2 (centre to centre)


Now consider ur mass to be m2. So the force exterted by u against the planet would be mg=Fgrav. So the value of g simplifies out to be,

g=(G*mass of planet)/d^2

For Jupiter,
mass=1.9*10^27 kg
radius=6.98*10^7 m
Therefore, g= approx 26

Answer 2

Well, considering the web wasn't around in 1987....I have an astronomy textbook from 1952 that gives Jupiter's equatorial diameter as 88640 miles and its mass as 316.94 Earth masses (which it gives as 6.6x10^21 tons - that's american tons, 1 ton has a weight of 200 pounds).

I've another book from around 1880, which says that Jupiter is 88,000 miles in diameter. It doesn't give a mass (I don't know why not, since it does have the orbital properties of the Galilean moons. It does say that the "density is onle one-fifth that of the earth". It does talk about its rapid rotation creating a significant centrifugal force on an object at the equator "Consequently a stone let fall on Jupiter would pass through but about thirty-nine feet the first second."

Answer 3

{(9.8 m/sec)^2}^16