i need help with a sq. roots problem?

Question

ok so i have to find the average of (sq. root of)5 and (the square root of) 45

and i don't know what to do when adding sq. roots...
can someone please help me?

anyone? HELP! i am really confused!

Answer 1

(sqrt)5+(surt)45
=(sqrt)5+(sqrt) 9*5
=(sqrt)5+3(sqrt)5
=(sqrt5){1+3}
=4(sqrt5)
Therefore the average is 4(sqrt5)/2=2(sqrt5)
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Answer 2

You cannot add two square roots unless they have the same number inside the square root such as if you had 2(square root of )3 and 3(square root of )3 that would become 5(square root of )3.
For this problem you would just write [(square root of)5 + (square root of)45]/2.
You cannot simplify the radical 45 further and have the same square root.

Answer 3

8to the sq root of 15

Answer 4

I think it's (sq root)80 over 2

Answer 5

square root of 5 is root 5 and square root of 45 is 3root5 so...
3 root 5 plus root 5 is 4 root 5

Answer 6

u r on ur own my friend hey try braking them down first like try the prime factorization thinggy like 45 break it down into 5 see and so forth so 5 is ur new root, so is gonna be 5 multiply by the square root of 5

try it

if its addition then u have to find wat the square root of 5 is and then add it by the aquare root of 45 but its better to use the prime factorization which is going to give u 5 so the square root of 5 plus the square root of 5 and there is ur answer
good luck

Answer 7

find the square roots at
http://www.math.com/students/calculators/source/square-root.htm

then add them together and divide by 2....

or else, its just (* = sq root sign)

(*5 + *45)/2

(thats the most exact answer)