can you explain in simple term why a triangular building stands longer in a quake than a rectangular building?

Answer 1

One of the vibration modes in an earthquake is a horizontal or side-to-side motion. A triangular building can be thought of as an arch. While it is better capable of handling vertical forces (i.e., the building itself), an arch can also deal with horizontal forces.

A rectangular building, however, has its weight resting on vertical pillars or walls. These stuctures are designed to hold the weight of the building that is pressing down vertically. They can't handle too much horizontal force else the weight of the building will come down at a angle outside the footprint of the walls.

An easy example is to take a sheet of cardboard and bend it in two. Put the free ends on a table and push the folded side back and forth. You should see that the side towards which you're pushing will resist the force. Now take another sheet of cardboard and make two parallel folds in it. As before, put the free ends down on a table. Now push one of the top edges in the same manner. You should be able to easily flatten the cardboard.

Answer 2

In a triangular building the foundation will be more good because the part at the top is not big as the bottom. But in a rectangular building it will fall down because it will not be stand as the foundation is not as strong as a triangular building.(I hope you understand. I am not very good in explaining, so there may be a bit confusion)

Answer 3

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Answer 4

the lower the center of the gravity the longer does a structure stand, just as the pyramids.

Answer 5

a triangle is rigid; it will not flex. A rectangle will "shift". Think of a rectangle made out of four pieces of wood. It will "shift", so- to- speak, unless you brace it with a diagonal piece of wood. What you have done is make two triangles.

Answer 6

it has a lower center of gravity