What is the value for m, and how do you solve the equation showing work?

Question

A mass m at the end of a spring vibrates with a frequency of 0.88 Hz. When an additional 680-g mass is added to m, the frequency is 0.60 Hz. What is the value for m, and how do you solve the equation showing work?

Answer 1

After a whole bunch of math my physics book says that
w^2 = k/m. Yours probably does too. So, what to do with it?

.88^2 = k/m
.60^2 = k/(m+680gm)

From the 1st one, k = (.88^2)*m. You can solve the 2nd for m from here.

Work:
W = F*d = -k*d^2

Answer 2

hj

Answer 3

what grade are you in?