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In an amusement park ride called The Roundup, passengers stand inside a 18.0m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane,

Suppose the ring rotates once every 4.50 . If a rider's mass is 59.0 , with how much force does the ring push on her at the top of the ride?

Suppose the ring rotates once every 4.50 . If a rider's mass is 59.0 , with how much force does the ring push on her at the bottom of the ride?

What is the longest rotation period of the wheel that will prevent the riders from falling off at the top?

2006-11-07 09:52:28 · 1 answers · asked by iknowu2jan 3 in Science & Mathematics Physics

1 answers

You will use the basic equation that the force has two components: The cetripidal force and the force of gravity

For the top of the ride:

f=m*((pi*D/4.5)^2/r - g)

For the bottom

f=m*((pi*D/4.5)^2/r + g)

The third is when the centripedal equals the force of gravity
The mass divides out
g=((pi*D)/rotation)^2/r

rotation = pi*D*sqrt(1/(g*r))

j

2006-11-07 11:01:45 · answer #1 · answered by odu83 7 · 0 0

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