How many combinations can i get if i have numbers 1-9 and the combination is 6 digits??

Question

NEED ANSWERS please NOW!!!

Answer 1

There are a few ways to find this, but the answer depends on whether we can repeat numbers in the combination and if the order matters.

If we cannot repeat numbers and order matters:
# combinations = 9*8*7*6*5*4 = 60480
There are 9 choices for the first digit, 8 for the second (because one is already taken), and so on. We multiply the choices for each digit to find the total number of choices.

If we can repeat numbers and order matters:
# combinations = 9^6 = 531441
There are 9 choices for each of the six digits.

If we cannot repeat numbers and order does not matter:
# combinations = 9!/(6!*3!) = 84

Answer 2

you have 6 digits, and each digit can be 1 of 9 numbers... so the number of permutations would be:

9 x 9 x 9 x 9 x 9 x 9 = 9^6 = 531441

if numbers could not repeat (i.e. each digit must be unique) it would be:

9 x 8 x 7 x 6 x 5 x 4 = 60480

Hope this helps!

Answer 3

If the numbers can be repeated, then you have
9^6 = 531,441

If the numbers can not be repeated,
9 x 8 x 7 x 6 x 5 x 4 = 60,480

Answer 4

60480

For the first digit you could chose from 9 numbers, for the second from 8, for the third from 7, and so on. You must do this for 6 different digits.

So..

9x8x7x6x5x4=60480

Answer 5

9^6=531441

if you include the digit 0, there are 10^6=1,000,000

Answer 6

The first digit can be one of 9 numbers, the next one of 8, the next one of 7, etc.

So...

9x8x7x6x5x4= 60,480

Answer 7

9! / (9-6)!

=9*8*7*6*5*4
= 60480