algerbra help?

Question

1 over x + 6 over xsquared divided by x + 216 over xsquared

Answer 1

We need some parentheses to know what you really mean...

Is this what you mean?
( 1/x + 6/x² ) / ( x + 216/x² )

If so, first get a common denominator (x²) for each of your fractions:
( x/x² + 6/x² ) / ( x^3 / x² + 216 / x² )

Now you can add the fractions:
[ ( x + 6 ) / x² ] / [ (x^3 + 216) / x² ]

Turn the division into a multiplication by inverting the second fraction:
[ ( x + 6 ) / x² ] * [ x² / (x^3 + 216) ]

The x² will cancel:
( x + 6 ) / ( x^3 + 216 )

The bottom equation can be factored (you can use synthetic division for this step):
( x + 6 ) / [ ( x + 6 ) ( x² - 6x + 36 ) ]

And the (x + 6) term will cancel:
1 / ( x² - 6x + 36 )

Answer 2

do you mean 1/(x+6)^2 / x+216/x^2
if that is the case flip one of the equations and multiply across using the distributive property after you will have to solve with quadratic formula

Answer 3

HERE'S A HINT: GET RID OF FRACTIONS BY MULTIPLYING BOTH SIDES BY 6. THEN, SUBTRACT EXPONENTS.

Answer 4

you need to write this better. IM me if you want more help. I have headset.

Answer 5

its 1/(x²-6x+36)