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a)what is the unbalanced force acting on it?
b)if the horizontal force exerted on the wheels by the road is 5600N, what force must be resisting the motion of the car?

2006-11-07 09:14:06 · 2 answers · asked by Joseph r 1 in Science & Mathematics Physics

2 answers

a) F=mxa=1100 x 3.4 = 3740 N


b) Unbalanced Force = Total Force - Resistance

so Resistance=Total Force - Unbalanced=5600 - 3740=1260 N

2006-11-07 09:24:25 · answer #1 · answered by Mech_Eng 3 · 2 0

a) F = ma = (1,100 kg)(3.4 m/s²)

b) F = 5400 N - (1,100 kg)(3.4 m/s²)

2006-11-07 17:33:55 · answer #2 · answered by Helmut 7 · 0 0

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