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9 answers

Too long to print but here's the website

(2^3021376)(2^3021377-1)

There are 1,819,050 digits

http://www.calendarhome.com/prime/perfect4.html

Please note that the highest perfect prime number currently known, will continue to change when a higher one is found.

2006-11-07 08:47:36 · answer #1 · answered by Melody 3 · 0 1

It is : 2^(p - 1) * (2^p - 1), where 2^p - 1 is the current highest known Mersenne prime.

As of September 06 2006, this is for p = 32 582 657. The perfect number then given by the above formula has about 19 616 715 decimal digits.

2006-11-07 09:11:59 · answer #2 · answered by Anonymous · 0 0

Here's a few:

n a(n)
1 6
2 28
3 496
4 8128
5 33550336
6 8589869056
7 137438691328
8 2305843008139952128
9 2658455991569831744654692615953842176
10 191561942608236107294793378084303638130997321548169216

2006-11-07 08:47:30 · answer #3 · answered by modulo_function 7 · 0 1

the formula for a perfect number is

2n−1(2n − 1)

where n is a prime number, so unless there is a highest prime number (unlikely) there is no highest perfect number.

2006-11-07 08:59:01 · answer #4 · answered by Random Precision 4 · 0 1

There is no highest perfect number. Just like there is no lowest pefect number. Numbers are infinite and can not be defined by an end or beginning...something like that.

2006-11-07 08:47:52 · answer #5 · answered by sleepy 6 · 0 2

218(219 - 1) = 137438691328. I think!

2006-11-07 08:49:30 · answer #6 · answered by huckypeep2 5 · 0 1

the amount of money i wish i had

2006-11-07 08:49:21 · answer #7 · answered by BlackicN 2 · 0 1

its either infinite or 8128

2006-11-07 08:48:44 · answer #8 · answered by Guitr Playrrr 2 · 0 2

infinite lol

2006-11-07 08:46:26 · answer #9 · answered by Anonymous · 0 2

1,000,000,000,000,000.

2006-11-07 08:47:31 · answer #10 · answered by Anonymous · 0 2

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