Too long to print but here's the website
(2^3021376)(2^3021377-1)
There are 1,819,050 digits
http://www.calendarhome.com/prime/perfect4.html
Please note that the highest perfect prime number currently known, will continue to change when a higher one is found.
2006-11-07 08:47:36
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answer #1
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answered by Melody 3
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It is : 2^(p - 1) * (2^p - 1), where 2^p - 1 is the current highest known Mersenne prime.
As of September 06 2006, this is for p = 32 582 657. The perfect number then given by the above formula has about 19 616 715 decimal digits.
2006-11-07 09:11:59
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answer #2
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answered by Anonymous
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Here's a few:
n a(n)
1 6
2 28
3 496
4 8128
5 33550336
6 8589869056
7 137438691328
8 2305843008139952128
9 2658455991569831744654692615953842176
10 191561942608236107294793378084303638130997321548169216
2006-11-07 08:47:30
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answer #3
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answered by modulo_function 7
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the formula for a perfect number is
2n−1(2n − 1)
where n is a prime number, so unless there is a highest prime number (unlikely) there is no highest perfect number.
2006-11-07 08:59:01
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answer #4
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answered by Random Precision 4
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There is no highest perfect number. Just like there is no lowest pefect number. Numbers are infinite and can not be defined by an end or beginning...something like that.
2006-11-07 08:47:52
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answer #5
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answered by sleepy 6
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218(219 - 1) = 137438691328. I think!
2006-11-07 08:49:30
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answer #6
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answered by huckypeep2 5
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the amount of money i wish i had
2006-11-07 08:49:21
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answer #7
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answered by BlackicN 2
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its either infinite or 8128
2006-11-07 08:48:44
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answer #8
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answered by Guitr Playrrr 2
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infinite lol
2006-11-07 08:46:26
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answer #9
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answered by Anonymous
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1,000,000,000,000,000.
2006-11-07 08:47:31
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answer #10
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answered by Anonymous
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