Reduce to lowest terms: 2x2 - 3x - 2 / 10 + x - 3x2?

Answer 1

I believe you meant (2x^2 - 3x - 2 )/ (10 + x - 3x^2) right?

Well we can rearrange the problem to look like (2x^2 - 3x - 2 )/ (- 3x^2+ x +10)

We now factor out the top and factor out the bottom.
[(2x +1) (x-2)] / [(-3x-5)(x-2)]

Since this is a fraction, we can cancel out the (x-2) because it is on top and the bottom.

We are left with:
(2x +1) / (-3x-5)

I think this is what you wanted, good luck and be careful of how you write your notation!

Answer 2

Hmmm, been a while since I've done math like this, but by the order of operations, you would take care of the multiplication (or division) first. Also reduce fractions, which I'll put into decimal for ease.

So:

2 x 2 - 3x - 2/10 + x - 3 x 2 -- becomes

4 - 3x - 0.2 + x - 6

now lets make subtraction of positives into the addition of negatives so we have pluses across the board and can move items around, and also re-express x as 1x

so...

4 - 3x - 0.2 + x - 6 -- changes into --

4 + -3x + -0.2 + 1x + -6

now with all like symbols we can switch the order...
4 + -6 + -0.2 + -3x + 1x

combine like terms

-2.2 - 2x

And that's it

Answer 3

First solve the top line,
2x2 - 3x -2 =
4-3x-2=
2-3x

bottom
10+x-3x6
10+x-18
x-8

so
2-3x / x-8

Hope thats what you were looking for

Answer 4

-2x - 2 1/5