1. Factorize each of these exprssions
(A) 3a² + 2a
(B) 12d² + 6
(C) 15y² - cy
(D) ab² + ac
Badly needed answers!!
2006-11-07 07:42:47 · 8 answers · asked by Danny D 1 in Science & Mathematics ➔ Mathematics
slider is correct.
Remember the distributive property?
a(b+c) = ab + ac
This is using it in reverse.
In part A, notice that there is an a in each term, so you can factor out the a's.
3a² + 2a = (3a)*a + 2 * a = a(3a + 2).
In part B, there aren't any letters in common but you can factor out numbers too.
12d²+6 = 6*2d² + 6*1 = 6(2d²+1)
The other parts use similar reasoning.
2006-11-07 07:55:35 · answer #1 · answered by Kylie 3 · 1⤊ 0⤋
A) a (3a + 2)
B) 6 (2d^2 + 1)
C) y (15y - c)
D) a (b^2 + c)
If they were set to zero, the you could come up with solution sets for some of them, but without that, this is as far as your can go...
2006-11-07 15:49:29 · answer #2 · answered by C D 3 · 0⤊ 0⤋
A) a (3a + 2)
B) 6 (2d^2 + 1)
C) y (15y - c)
D) a (b^2 + c
hopes it helps!!
2006-11-07 16:28:31 · answer #3 · answered by rena 2 · 0⤊ 0⤋
A. a(3a + 2)
B. 6(d^2 + 1) or 6[d - (-1)^1/2] [d + (-1)^1/2]
C. y(15y - c)
D. a(b^2 + c)
2006-11-07 16:06:07 · answer #4 · answered by cimpuazaj c 1 · 0⤊ 0⤋
E=mc 2
2006-11-07 15:44:08 · answer #5 · answered by ? 7 · 1⤊ 1⤋
(A) a(3a+2)
(B) 6(2d^2+1)
(C) y(15y-c)
(D) a(b^2+c)
2006-11-07 15:47:21 · answer #6 · answered by slider 2 · 2⤊ 0⤋
OMG - get out your math book and study.
Take a breath, you can figure this out.
2006-11-07 15:44:34 · answer #7 · answered by Anonymous · 0⤊ 1⤋
HINT:
a(b + c) = ab + ac
(It's reversible.):
ab + ac = a(b + c)
2006-11-07 15:49:52 · answer #8 · answered by Helmut 7 · 1⤊ 0⤋