use the remainder theorem and the factor theorem to determine whether (c+5) is a factor of?

Question

(c^4+7c^3+6c^2-18c+10)

a.) The remainder is 0 and, therefore, (c+5) is a factor of (c^4+7c^3+6c^2-18c+10)

b.)The remainder is 0 and, therefore, (c+5) isnt a factor of (c^4+7c^3+6c^2-18c+10)

c.)The remainder isnt 0 and, therefore, (c+5) is a factor of (c^4+7c^3+6c^2-18c+10)

d.)The remainder isnt 0 and, therefore, (c+5) isnt a factor of (c^4+7c^3+6c^2-18c+10)

Answer 1

If we use long division or synthetic division, we
see that -5 is a zero of c^4+7c^3+6c^2-18c+10.
So c + 5 is a factor and the first statement is
true, by the factor theorem.

Answer 2

if (c+5) have been a component of (c^4 + 7c^3 + 6c^2 - 18c + one million), it may could bypass into it gently (that is, without the rest), yet this operation provides a the remainder of -9, so it won't be able to be a component. that is totally no longer ordinary to tutor you the calculations right here, although that is purely a branch issue ....

Answer 3

(-5)^4+7(-5)^3+6(-5)^2-18(-5)+10 = 0
I don't really understand why you have four parts, a-d?