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An elevator hangs from a cable that goes around a pulley of diameter 7.7 feet. If the elevator climbs 181 feet in 17.2 seconds at a constant speed, determine the angular velocity of the pulley in revolutions per second. Your answer must be accurate to three decimal places.

2006-11-07 06:20:48 · 2 answers · asked by AppleCard! 2 in Science & Mathematics Physics

2 answers

The linear speed of the cable is
181/17.2 ft/sec

one revolution is equal to the circumference of the pulley or 7.7 *pi ft/revolution

so the angular speed is
(181/17.2)/(7.7*pi) rev/sec
=.435 rev/sec

j

2006-11-07 06:28:30 · answer #1 · answered by odu83 7 · 0 0

As I said.

2006-11-07 14:32:12 · answer #2 · answered by ag_iitkgp 7 · 0 0

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