2006-11-07 05:57:28 · 3 answers · asked by j cool 1 in Science & Mathematics ➔ Mathematics
Hi Dear Ruth ;
{ as you know Sum ( angles of trapezoid) = 360
if ' a ' & ' b ' & ' c ' & ' d ' are angles of trapezoid so
a + b + c + d = 360 } ....
▪ Step 1
a = 6x - 4 , b = 5x + 1 , c = 4x , d = 3x + 3
as , a + b + c + d = 360 so ;
6x - 4 + 5x + 1 + 4x + 3x + 3 = 360
[ 6x + 5x + 4x + 3x ] + [ -4 + 1 + 3 ] = 360
18x + 0 = 360
x = 360 / 14
x = 20
▪ Step 2
as x = 20
a = 6x - 4 ; 6(20) - 4 = 116
b = 5x + 1 ; 5(20) + 1 = 101
c = 4x ; 4(20) = 80
d = 3x + 3 ; 3(20) + 3 = 63
so we have ;
a = 116 ; b = 101 , c = 80 , d = 63
Good Luck dear ♣
2006-11-07 06:46:15 · answer #1 · answered by sweetie 5 · 2⤊ 0⤋
If a,b,c,d are the angles, then 6x-4+5x+1+4x+3x+3=360.
So, 18x=360, so x=360/18 = 20.
So, a=116, b=101, c=80, d=63.
2006-11-07 14:12:37 · answer #2 · answered by yljacktt 5 · 0⤊ 0⤋
a+b+c+d = 360
So, 6x-4 + 5x+1 + 4x + 3x+3 = 360
18x = 360
x = 20
So, a = 116
b = 121
c = 80
d = 63
2006-11-07 14:16:13 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋