((Log(100^3))^2) + ( 6 root of 117649)=?

Answer 1

Hello Dear ;

▪ Step 1
as you know 100 ³ = 1,000,000 = 10 ^ 6
so we have
log (100 ³) = log(10^6) = 6
6 ² = 36
√ (117649) = 343
343 = 49 * 7 = (7 * 7) * 7 = 7 ³
³ √(343) = 7

▪ Step 2
(log(100 ³) ²) + (117649^(1/6)) = 36 + 7 = 43


Good Luck Dear.

Answer 2

log(100^3) = log(10^6) = 6
6^2 = 36

For the other part, I'm assuming you mean the 6th root of that number. That would be the same as the cube root of the square root.
sqrt(117649) = 343
cuberoot(343) = 7

Putting it all together:
(log(100^3)^2) + (117649^(1/6)) = 36 + 7 = 43

Your answer is:
43

Answer 3

((Log(100^3))^2) = 36
( 6 root of 117649) = 2058
((Log(100^3))^2) + ( 6 root of 117649)=2094