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I know how to do them, but not the way my teacher wants me to, so if i show my work in my assignment, she'll c that ill doin it wrong. cuz all i do is guess and check and i find the answer fast than any1 doin the steps.

PLEASE sove these and show your work.

1.) 5x + 7 = 3x + 21

2.) 3x - 2(5 - x) = -3(x - 10) + 3x

3.) 5(x + 1) = 3(2x + 3) + 5

2006-11-07 05:41:33 · 5 answers · asked by martha l 1 in Education & Reference Homework Help

5 answers

1. 5x + 7= 3x + 21
-3x -3x
2x + 7 = 21
-7 -7
2x = 14
/2 /2
x = 7

2. 3x - 2 (5-x) = -3(x-10) + 3x
3x - 10 - 2x = -3x + 30 + 3x
x - 10=30
x=40

3. 5( x+1) = 3(2x +3) + 5
5x + 5 = 6x+9 + 5
5x+5=6x+14
5=x+14
x=-19

2006-11-07 05:48:41 · answer #1 · answered by Sarah T 3 · 0 0

5X + 7 = 3X +21 all you have to do is move one to the other side
-3x -3x
=2x + 7 =21 then you need to get x by itself subtract 7 from 21
-7 -7
= 2x = 14 then divide 2x by 14
2x/ 2x = 14/2x
x = 7
the second one used distrubutive property and do the parenthesis first
on you done add all the x's in both then move an x just like the first one and do the same thing by subtractin and dividing you'll get all the answers
is that algebra 1
the 3rd one is pretty easy too

2006-11-07 13:56:15 · answer #2 · answered by LYNN 4 · 0 0

5x+7=3x+21, subtract 7 from each side
5x=3x+14, subtract 3x from each side
2x=14, divide both sides by 2
x=7

3x-2(5-x)=-3(x-10)+3x, do multiplication
3x-10+2x=-3x+30+3x, simplify
5x-10=30, add 10 to each side
5x=40, divide each side by 5
x=8

2006-11-07 13:52:58 · answer #3 · answered by Anonymous · 0 0

1. 5x+7=3x+21
5x-3x=21-7
2x=14
x=14/2
x=7
2. 3x-2*(5-x)=-3*(x-10)+3x
3x-10+2x=-3x+30+3x
3x+2x+3x-3x=30+10
5x=40
x=8
3. 5*(x+1)=3*(2x+3)+5
5x+5=6x+9+5
5x-6x=-5+5+9
-x=9
x=-9

2006-11-07 13:56:20 · answer #4 · answered by baby 3 · 0 0

simple algebra

1.) 5x+7=3x+21
-3x -3x
------------------------
2x+7=21
-7 -7
---------------
2x= 14
2x/2=14/2

x=7

now do the others on your own. on 2 make sure you mult 2 by 5-x before going through the steps I showed you and also on the other side. If you need more help let me know.

2006-11-07 13:45:01 · answer #5 · answered by ssccstudent2004 2 · 0 1

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