1: In a square pyramid the edge of the base is 24 inches, the slant height is 20 inches, and the altitude is 16 inches. Find the lateral area (the surface area of the triangular sides only).
850 sq. in
900 sq. in
960 sq. in
990 sq. in
2: In a square pyramid the edge of the base is 24 inches, the slant height is 20 inches, and the altitude is 16 inches. Find the total surface area (the surface area of all sides of the pyramid).
960 sq. in
1115 sq. in
1230 sq. in
1536 sq. in
3: In a square pyramid the edge of the base is 24 inches, the slant height is 20 inches, and the altitude is 16 inches. Find the volume.
2785 cu. in.
2568 cu. in.
3140 cu. in.
3072 cu. in
4: An open grain hopper is in the form of an upside-down square pyramid (with the base on top and vertex below). The base is 10 square feet, the slant height is 13 feet, and the altitude 12 feet. How many bushels of wheat can it hold level full if 1 bushel occupies 1 cubic foot?
Tip: Find
2006-11-07 05:33:52 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
How did you ever even have kids without knowing this stuff?
2006-11-07 05:37:00 · answer #1 · answered by TODSHISHLER 4 · 0⤊ 0⤋
I got:
1. 960", to find the area of the triangles just take the base and
multiply it by the hight and divide the answer by 2. (A=bh/2,
A=(24)(20)/2, understand?) Then multiply that answer by the
number of sides (that happens to be 4) to find the area of all
the triangular sides put together.
2.1536, just add the area of the pyramid's base to the answer
above. The area of the base is the length times the width
(A=bh), and the base is a square so the sides are all equal.
The side length is 24, so multiply 24 by 24 to get the area.
Then add the answer to the above answer.
Then I don't know how to do the rest.
2006-11-07 05:41:21 · answer #2 · answered by Titainsrule 4 · 0⤊ 0⤋
1) 4*20*(24/2) = 960
2) 960+(24^2) = 960+576 = 1536
3) (24^2 * 16)/3 = (576*16)/3 = 3072
4) (10^2 * 12)/3 = 400
2006-11-07 06:03:11 · answer #3 · answered by yljacktt 5 · 0⤊ 0⤋
place all of them in a column with the decimals coated up in case you need to. a million.2 a million.12 a million.02 0.22 So, the 0 until eventually now the decimal is the obtrusive small quantity Then something have ones. So, examine the tenths (the 1st quantity previous the decimal.) you have 0, a million, 2. So, a million.02 is next, accompanied via a million.12, accompanied via a million.2 It doesnt count with reference to the hundredths (the 2nd quantity previous the decimal) because of the fact not one of the tenths numbers are the comparable. If, say you had a million.22 and a million.24, then you certainly might prefer to think approximately the hundredths. sturdy success!
2016-10-15 12:00:03 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1. 960 sq. in.
2. 1536 sq. in
3. 3072 cu in.
4. 400
2006-11-07 05:48:19 · answer #5 · answered by ag_iitkgp 7 · 0⤊ 0⤋
1(c)
2(d)
3(d)
4: 40 bushels
I'm not gonna give the proof for them, you have to work it out yourself. But if you are really in trouble then contact me by IM or email.
2006-11-07 05:42:45 · answer #6 · answered by Anonymous · 1⤊ 0⤋
Oh why didnt they have yahoo answers when I was in school so i too could have others do my homework =)
2006-11-07 05:36:41 · answer #7 · answered by Robbyz3 2 · 0⤊ 0⤋
you can't have a SQUARE pyramid all dimensions are triangle shapes .
2006-11-07 05:42:27 · answer #8 · answered by Tired Old Man 7 · 0⤊ 1⤋
http://search.yahoo.com/bin/search?fr=ybr_sbc&p=free%20math%20help
one of these should help..
2006-11-07 05:42:48 · answer #9 · answered by rcsanandreas 5 · 0⤊ 0⤋