ayy dudes help with this math question!?

Question

What is the 12th term of a geometric sequence in which the common ratio is 2 and the first term is 12?

Answer 1

Your sequence is:
12, 24, 48, 96, 192, ...

You can see the pattern:
a(1) = 12 * 1 = 12
a(2) = 12 * 2 = 24
a(3) = 12 * 4 = 48
a(4) = 12 * 8 = 96
a(5) = 12 * 16 = 192
...
In general:
a(n) = 12 * 2^(n-1)

So:
a(12) = 12 * 2^11
a(12) = 12 * 2,048
a(12) = 24,576

Answer 2

a(n) = a(1) * k ^ (n - 1)
a(12) = 12 * (2 ^ 11)

Answer 3

t12=ar^11
=12*2^11