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9 answers

Friend,
let the number be y
3*y=9
y=9/3
y=3
So the number is 3

2006-11-07 05:13:23 · answer #1 · answered by JACKREX 2 · 0 0

3

2006-11-07 05:18:02 · answer #2 · answered by Brenmore 5 · 0 0

3

2006-11-07 04:50:00 · answer #3 · answered by Anonymous · 0 0

3 time 3 is 9

2006-11-07 04:50:55 · answer #4 · answered by raj 7 · 0 0

richard is x and ruel is y. from the difficulty all of us comprehend that x+y=60. additionally, (x-9)=2(y-9). from the 1st equation all of us comprehend that x=60-y, so, ((60-y)-9)=2(y-9). via simplifying this we are able to get the value of y: ((60-y)-9)=2(y-9) (51-y)=2(y-9) 51-y=2y-18 51=2y-18+y 51=3y-18 51+18=3y sixty 9=3y y=13 x=60-y x=60-13 x=40 seven As for the 2d difficulty, the 1st digit is x and the 2d is y. so, x+y=9, and...it does not make sense while u suggested that the huge variety is 12 situations the ten's digit, so i can't somewhat remedy that until eventually u describe this in extra info. The 0.33 difficulty, the three numbers are x,y, and z. What all of us comprehend is that: x+y+z=fifty seven x=y-2 y=z-2 x, y, and z are unusual integers. from the 2d equation all of us comprehend that y=x+2, to that end, x+2=z-2. via including 2 on the two aspects, we see that x+4=z. so we've the value of y and z in terms of x. via inputting those values into the 1st equation, we get x+(x+2)+(x+4)=fifty seven. via simplifying this, we get 3x+6=fifty seven. via subtracting 6 on the two area, we come to the effect 3x=51. dividing the two aspects via 3 supplies us the value of x, x=17. Now that all of us comprehend x=17, y=x+2, so y=17+2=19. y=z-2, so 19=z-2, z=21 ok, so i'm getting the 2d question. the respond is 36.

2016-10-21 10:28:56 · answer #5 · answered by Anonymous · 0 0

This is simple, 3x3=9

2006-11-07 04:54:16 · answer #6 · answered by ruth4526 7 · 0 0

3x=9 divide by 3

x=3

2006-11-07 04:59:09 · answer #7 · answered by unan1m0us 5 · 0 0

Certainly it is 3 !

2006-11-07 04:50:55 · answer #8 · answered by Alrahcam 4 · 0 0

3

3x3=9

2006-11-07 04:49:54 · answer #9 · answered by BabyGirl 3 · 0 0

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