I need help factoring this out. I tried that guess and check strategy and it's driving mecrazy. PLEASE HELP!
2x^2-5x-12
2x^2+10x-72
x^2+5x-6
2006-11-07 03:34:16 · 7 answers · asked by shipis 3 in Science & Mathematics ➔ Mathematics
2x^2-8x+3x-12
2x(x-4)+3(x-4)
2x+3 = 0 or x-4= 0
x = -3/2 or x = 4
2x^2+10x-72
2x^2+18x-8x-72
2x(x+9)-8(x+9)
x = 4 or x = -9
x^2+6x-x-6
x-1 = 0 or x+6 = 0
x = 1 or x = -6
2006-11-07 03:37:27 · answer #1 · answered by Anonymous · 0⤊ 0⤋
2X^2 - 5x - 12= (2x + 3)(x - 4)
2x^2 + 10x - 72 = (2x - 8)(x + 9)
x^2 + 5x -6 = (x + 6)(x - 1)
2006-11-07 11:46:08 · answer #2 · answered by Anonymous · 0⤊ 0⤋
A- (2x + 3)(x - 4)
B- 2(x + 9)(x - 4)
C- (x + 6)(x - 1)
2006-11-07 16:34:42 · answer #3 · answered by rena 2 · 0⤊ 0⤋
A) (2x + 3)(x - 4)
B) 2(x + 9)(x - 4)
C) (x + 6)(x - 1)
2006-11-07 11:39:03 · answer #4 · answered by Dave 6 · 0⤊ 0⤋
2x^2-5x-12
=2x^2-8x+3x-12
=2x[x-4]+3[x-4]
=[2x+3][x-4]
2x^2+10x-72
=2x^2+18x-8x-72=2x[x+9]-8[x+9]
=[2x-8][x+9]
=2[x-4][x+9]
Please try doing these
problems yourself. It is so
much fun when you get it right
x^2+5x-6
=x^2+6x-x-6
=x[x+6]-1[x+6]
=[x-1][x+6]
2006-11-07 12:11:00 · answer #5 · answered by openpsychy 6 · 0⤊ 0⤋
(2x+3)(x-4)
(2x-8)(x+9)
(x+6)(x-1)
2006-11-07 11:38:03 · answer #6 · answered by pcolaengr1 3 · 0⤊ 0⤋
1.2x^2-5x-12
=2x^2-8x+3x-24
(2x+3)(x-4)
2.2x^2+10x-72
=2x^2+18x-8x-72
=(2x-8)(x+9)
=>2(x-4)(x+9)
3.x^2+5x+6)
x^2+3x+2x+6
(x+2)(x+3)
2006-11-07 11:41:19 · answer #7 · answered by raj 7 · 0⤊ 0⤋