solve the formula for the indicated variable.?

Question

1. A= lW

solve for L

2. 9/5C +32 =F

solve for C

3. A= 1/2 bh

solve for h.

thank - you, oh so much

Answer 1

The trick is that you can do the same thing to both sides of an equation:

1. Divide both sides by W: L = A/W

2. Subtract 32 and multiply by 5/9: C = (F - 32) * 5 / 9

3. Multiply both sides by 2 and divide by b: h = 2A/b

Simple steps, once you have the hang of it.

Answer 2

It's simple algebra.

1. A = LW ==> L = A/W, by dividing both sides by W

2. (9/5)C + 32 = F ==> C = (5/9)(F - 32), by subtracting 32 form both sides and multiplying both sides by 5/9

3. A = (1/2)bh ==> h = 2A/b, by multiplying both sides by 2 and dividing both sides by b

Answer 3

1.A=LW
dividing by W
L=A/W

2.(9/5)C+32=F
adding -32
(9/5)C=F-32
multiplying by(5/9)
C=(F-32)(5/9)

3.A=(1/2)bh
multiplying by 2
2A=bh
dividing by b
h=2A/b

Answer 4

Solve for L

A = LW

A/W = LW/W

A/W = L

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Solve for C

9/5C + 32 = F

5/9(9/5)C + 32 = 5/9F

C + 32 = 5/9F

C + 32 - 32 = 5/9F - 32

C = 5/9F - 32

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Solve for h

A = 1/2bh

2A = 2(1/2)bh

2a = 1bh

2A = bh

2A / b = bh/b

2A / b = h

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Answer 5

a million. a = F/m 2. r = v/S 3. v = m/D it somewhat is basic... you could draw a triangle like this: --- v --- S --- r and you will see that: S=v/r, v=Sr, r=v/s or, worst case state of affairs, only put in some random numbers, and verify out to discern the formulation like 2=6/3, you will see that 3=6/2, 6=3*2, etc... desire this enables :)

Answer 6

L=A/W

C= 5/9(F-32)

h= (2A)/b