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I know this is a compound of calcium Carbon and oxygen, but what is the correct name. Is it "Calcium oxide"?

2006-11-07 03:17:37 · 15 answers · asked by ZebraheadMoFo 2 in Science & Mathematics Chemistry

15 answers

Ca is calcium. CO3 is carbon. this makes the finishes product calcium carbonate

2006-11-07 03:21:26 · answer #1 · answered by Anonymous · 0 2

Calcium Carbonate

2006-11-07 03:19:28 · answer #2 · answered by pcolaengr1 3 · 0 0

Calcium carbonate

2006-11-08 05:22:22 · answer #3 · answered by marizani 4 · 0 0

A lot of people have told you it is calcium carbonate which is correct. It is an ionic compound with each molecule made from a Ca ++ ion (positive charge 2) and a carbonate ion (CO3)-- (negative charge two). The Carbon and 3 Oxygen atoms in the carbonate ion are held together by covalent forces. The Ca ion and Carbonate ion are held together ionic (charge) attraction. Hope that helps a bit more.

2006-11-07 04:29:35 · answer #4 · answered by Anonymous · 0 0

CaCO3 = Calcium Carbonate.

2006-11-07 03:20:27 · answer #5 · answered by sanjayd_411 2 · 0 0

CaCO3 is Calcium carbonate ,the main constituent of chalk,marbles, limestone , snail shells etc.
The main cause of hardwater. This is a white solid ( powder).
On the other hand,CaO is calcium oxide popularly called quicklime or burnt lime this is a white crystalline solid.
If you heat CaCO3 to about 825 degree centigrade, it decomposes to give CaO and gaseous CO2 is also released.

Hope this is good enough for what u need! If you need some more I recommend wikipedia. just google and it will turn up!

2006-11-07 04:18:33 · answer #6 · answered by Chinwe A 2 · 0 0

Calcium Carbonate (limestone)

2006-11-07 04:25:49 · answer #7 · answered by Treat 2 · 0 0

Calciumtrioxocarbonate(IV) or calcium carbonate

2006-11-07 10:18:28 · answer #8 · answered by Anonymous · 0 0

Calcium Carbonate

The principal constituent of:

Chalk
Limestone
Marble
Seashells


Calcium Oxide is CaO

2006-11-07 03:19:44 · answer #9 · answered by Anonymous · 1 0

Calcium Carbonate

Details on the link below.....

2006-11-07 03:29:21 · answer #10 · answered by Anonymous · 0 0

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